Arrangements of BANANA

The word has repeated letters: three A's and two N's out of six letters.

Divide the total permutations by the factorials of the repeat counts.

1. 1. Apply the multiset permutation formula

   BANANA has $6$ letters with $3$ A's, $2$ N's and $1$ B.

   $$\frac{6!}{3!2!1!}=\frac{720}{12}=60$$

Answer: 60